Original practice · fully worked
Original variant: combined count from exclusive inspection classes
Twenty components are inspected independently. Each is classified as cosmetic rework with probability 0.30, functional rework with probability 0.20, or acceptable otherwise. Let X and Y be the counts in the two rework classes. Calculate Var(X+Y).
- A
1.20 - B
3.20 - C
5.00 - D
7.40 - E
9.80
Answer and calculation
For each component, membership in either rework class has probability 0.50. Therefore X+Y is Binomial(20,0.50) and has variance 20(0.50)(0.50)=5, so choice C.
Setup
Setup
Combine the two mutually exclusive rework labels into one indicator for whether a component requires any rework.
prework=0.30+0.20=0.50 Model
Model
The combined count is binomial because the twenty component classifications are independent.
X+Y∼Binomial(20,0.50) Compute
Compute
Apply the binomial variance formula.
Var(X+Y)=20(0.50)(1−0.50)=5 Answer
Answer
The combined rework-count variance is 5.00.
5.00(C)