Independent solution

How to solve this Bayes’ Theorem question

Setup

Setup

Under each possible source, compute the binomial likelihood of observing exactly one incident in 30 independent trials.

LX=30(0.10)(0.90)29L_X=30(0.10)(0.90)^{29}
LO=30(0.02)(0.98)29L_O=30(0.02)(0.98)^{29}

Model

Model

Multiply each exact-one likelihood by its source prior and normalize the source-X weight.

Pr(XI=1)=0.20LX0.20LX+0.80LO\Pr(X\mid I=1)=\frac{0.20L_X}{0.20L_X+0.80L_O}

Compute

Compute

Substituting the two likelihoods and priors into Bayes' formula gives posterior probability 0.0956576 for source X.

Pr(XI=1)=0.0956576\Pr(X\mid I=1)=0.0956576

Answer

Answer

The posterior source-X probability rounds to 0.10, corresponding to choice A.

0.10(A)\boxed{0.10\quad\text{(A)}}