Independent solution

How to solve this Hypergeometric Distribution question

Setup

Setup

Use an unordered six-item sample because all subsets of six claims are equally likely.

#{all samples}=(136)=1716\#\{\text{all samples}\}=\binom{13}{6}=1716

Model

Model

Choose the required number independently within each claim category.

#{favorable}=(21)(42)(73)\#\{\text{favorable}\}=\binom21\binom42\binom73

Compute

Compute

Evaluate the favorable count and divide by the common sample-space count.

(21)(42)(73)=2(6)(35)=420\binom21\binom42\binom73=2(6)(35)=420
Pr=4201716=35143=0.2447552\Pr=\frac{420}{1716}=\frac{35}{143}=0.2447552

Answer

Answer

The probability rounds to 0.245.

0.245(D)\boxed{0.245\quad\text{(D)}}