Original practice · fully worked
Original variant: quantify the failure of event additivity
A fair six-sided selector outputs one of the integers 1 through 6. Define U={1,2,3}, V={3,4}, and W={4,5}. Calculate [P(U)+P(V)+P(W)]-P(U union V union W).
- A
1/12 - B
1/3 - C
2/3 - D
5/6 - E
7/6
Answer and calculation
The three individual probabilities sum to 7/6, while their union contains five of the six outputs and has probability 5/6. The additivity gap is 2/6=1/3, choice B.
Setup
Setup
Compute the three event probabilities from their numbers of selector outcomes.
Pr(U)=63,Pr(V)=62,Pr(W)=62 Model
Model
Identify the distinct outputs included in at least one event.
U∪V∪W={1,2,3,4,5} Pr(U∪V∪W)=65 Compute
Compute
Subtract the union probability from the sum of the marginals.
(63+62+62)−65=62=31 Answer
Answer
The overlap creates an additivity gap of one third.
31(B)