This Exam P sample reference tests Mutually Exclusive Outcomes. The two complement statements identify the endpoint category probabilities as 0.20 each. Subtracting them from the 0.75 lower-stage total leaves 0.35 for the requested category, choice C.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 0.20 is the probability of either of the two categories recovered directly by complementation, not the requested middle category.
BThe value 0.25 divides the 0.75 three-category total equally, ignoring that two component probabilities are already fixed at 0.20.
DThe value 0.48 cannot satisfy the lower-category equation because 0.20+0.48+0.20=0.88 rather than 0.75.
EThe value 0.65 is impossible once p0=p2=0.20: those three category masses would total 1.05 rather than the supplied 0.75.
Original practice · fully worked
Original variant: recover a route share from pair totals
Each parcel is assigned to exactly one of four routes: North, East, South, or West. The combined shares for North-or-East, East-or-South, and North-or-South are 0.55, 0.60, and 0.45, respectively, while the West share is 0.20. Determine the East share.
A 0.20
B 0.25
C 0.30
D 0.35
E 0.40
Variant answer in brief
Adding the first two pair totals and subtracting the third leaves twice the East share. Thus 2E=0.55+0.60-0.45=0.70 and E=0.35, choice D.
Setup
Setup
Translate the three disjoint-route pair totals into equations.
N+E=0.55
E+S=0.60
N+S=0.45
Model
Model
Combine the equations so the North and South shares cancel.
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