Independent solution

How to solve this Equally Likely Outcome Counting question

Setup

Setup

The two fair dice produce 36 equally likely ordered outcomes.

N(Ω)=62=36N(\Omega)=6^2=36

Model

Model

An absolute difference below three allows differences zero, one, and two. Count six equal pairs and both orders for each unequal pair.

N(D1D2<3)=6+2(5+4)=24N(|D_1-D_2|<3)=6+2(5+4)=24

Compute

Compute

The favorable counts are six, ten, and eight for the three allowed differences, totaling 24 of the 36 outcomes.

Pr(D1D2<3)=2436=23\Pr(|D_1-D_2|<3)=\frac{24}{36}=\frac23

Answer

Answer

The requested dice probability is two thirds.

23(E)\boxed{\frac23\quad\text{(E)}}