Independent solution

How to solve this Annuity Exhaustion Drop Payment question

Setup

Setup

Accumulate the twenty beginning-of-year deposits at 8.16% to the withdrawal date. Withdrawals of 3,000 begin immediately, so they form an annuity-due.

F=1000s¨200.0816=50382.16F=1000\ddot s_{\overline{20}|\,0.0816}=50382.16

Model

Model

Value the first twenty-six withdrawals plus the final drop payment at the same date. The drop payment occurs one period after the last full payment and is discounted accordingly.

50382.16=3000a¨260.04+X(1.04)2650382.16=3000\ddot a_{\overline{26}|\,0.04}+X(1.04)^{-26}

Compute

Compute

The fund is 50,382.16. Solving the withdrawal equation gives the final payment X = 1,430.

X=1430X=1430

Answer

Answer

The calculation gives 1430 for annuity exhaustion drop payment, matching published choice C.

X=1430(C)\boxed{X=1430\quad\text{(C)}}

Calculator reproduction

BA II Plus keystrokes

Check END/BGN, period, sign, TVM, and cash-flow setup

  1. 2nd CLR TVM; 20 N; 8.16 I/Y; 1000 +/- PMT; 0 PV; 2nd PMT; 2nd SET; 2nd QUIT; CPT FV50382.16BGN mode for the deposits.