This Exam FM sample reference tests Arithmetic-Increasing Perpetuity-Due. The two receipts are worth 1821927.11 today. An arithmetic perpetuity-due has value X times 26 plus the 1000 increments' value 650000. Solving gives X = 45074.12, choice A.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
BChoice B values the arithmetic increments as an increasing annuity-immediate and shifts the level component inconsistently.
CChoice C omits discounting of the second million-dollar receipt.
DChoice D treats the 1000 increase as a 1000 level perpetuity rather than an arithmetic gradient.
EChoice E values only the arithmetic increments and allocates the remainder over too few payments.
Original practice · fully worked
Original variant: level replacement for a finite arithmetic annuity
Five annual payments occur at times 0 through 4. The first is 2,000 and each later payment is 100 larger. At a 5% yield, replace them by five equal payments on the same dates. Determine the level payment.
A 2,100.00
B 2,150.67
C 2,190.25
D 2,224.81
E 2,250.00
Variant answer in brief
The arithmetic stream has present value 9956.78. Dividing by the five-payment annuity-due factor gives a level payment of 2190.25, choice C.
Setup
Setup
Discount the five arithmetic payments at their actual dates.
PV=t=0∑41.05t2,000+100t=9,956.7773
Model
Model
Let L be the equal payment on dates zero through four.
PV=La¨5∣0.05
Compute
Compute
Divide by the due-annuity factor.
L=4.54595059,956.7773=2,190.2520
Answer
Answer
The equivalent level payment is 2190.25, choice C.
The 2210-page Financial Mathematics Proof Manual reorganizes 461 verified Exam FM solutions by syllabus skill and adds formula proofs, error patterns, and original worked practice.