This Exam FM sample reference tests Accumulation Followed by a Perpetuity. Equating the 45-deposit accumulation to the perpetuity price makes the 45-year accumulation factor equal to 10. Thus i = 5.2500% and the fund is 1199.99, choice C.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AChoice A results from valuing the perpetuity at i rather than the stated 1.2i.
BChoice B shortens the deposit accumulation while retaining the same perpetuity payment.
DChoice D uses 75.60 divided by i and omits the 1.2 multiplier in the perpetuity yield.
EChoice E treats the forty-five deposits as an annuity-due and advances every deposit one year.
Original practice · fully worked
Original variant: number of deposits supporting a perpetuity
A saver deposits 10 at each year-end into an account earning 4% effective. Immediately after the last deposit, the balance buys a perpetuity-immediate priced at 5% and paying 14.8890 annually. How many deposits were made?
A 16
B 18
C 20
D 22
E 25
Variant answer in brief
The perpetuity costs 297.7800. Solving 10s-angle-n at 4% equal to that amount gives n = 20, choice C.
Setup
Setup
Translate the perpetuity payment into the fund required at purchase.
X=0.0514.8890=297.780
Model
Model
The year-end deposits accumulate as an annuity-immediate.
10sn∣0.04=297.780
Compute
Compute
Isolate the accumulation factor and solve its exponent.
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