This Exam FM sample reference tests Annuities. Each year's m fractional payments accumulate to 1.0331 at year-end, so annuity X has value 1.0331 times the ten-year annuity factor. Equating it to five biennial payments and using the two-year accumulated-annuity factor 2.075 gives P = 2.1437, choice E.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AChoice A (1.94) does not satisfy the equality of the ten annualized fractional blocks and five biennial payments; no distinct standard one-step error is identifiable.
BChoice B (2.01) does not satisfy the equality of the ten annualized fractional blocks and five biennial payments; no distinct standard one-step error is identifiable.
CChoice C (2.03) does not satisfy the equality of the ten annualized fractional blocks and five biennial payments; no distinct standard one-step error is identifiable.
DChoice D (2.07) does not satisfy the equality of the ten annualized fractional blocks and five biennial payments; no distinct standard one-step error is identifiable.
Original practice · fully worked
Original variant: within-year accumulation factor inferred from an equivalent biennial annuity
A ten-year annuity pays equal fractions throughout each year. The accumulated value at each year-end of that year's fractional payments is A. An equivalent annuity pays 2.40 at years 2, 4, 6, 8, and 10. The two-year accumulated-annuity factor is 2.10. Calculate A.
A 1.03
B 1.09
C 1.14
D 1.20
E 1.26
Variant answer in brief
The annuity-value cancellation gives the biennial payment equal to A times the two-year accumulated-annuity factor. Therefore A = 2.40/2.10 = 1.1429, choice C.
Setup
Setup
Annualize each year's fractional block to amount A at the corresponding year-end.
PVX=Aa10∣i
Model
Model
Equating with the five biennial payments yields the same simplification as grouping the ten years in pairs.
2.40=As2∣i
Compute
Compute
Using the supplied two-year factor gives A = 1.142857.
A=2.102.40=1.14285714
Answer
Answer
The within-year accumulated amount is 1.1429, selecting choice C.
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