Probability · multivariate diagnostic PDF

Exam P Multivariate & Risk Models: 30 Worked Problems

Build control over joint densities, conditioning, covariance, sums, order statistics, and normal approximations with complete five-choice diagnostics.

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Version 1.0.0 · Updated 2026-08-24

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One original Exam P practice question with full solution

The marginal variances of two calibration errors are Var(X)=4 and Var(Y)=25. Their correlation is not specified and may take any feasible value from -1 through 1. An index is defined as Z=3X-2Y+7. Calculate the largest possible value of Var(Z).

  1. 16
  2. 100
  3. 120
  4. 136
  5. 256

Writing Cov(X,Y)=10rho gives Var(Z)=136-120rho. This is largest at rho=-1, where the variance is 256, so choice E.

Setup

Express covariance through the unknown correlation and the two standard deviations.

Cov(X,Y)=ρ(2)(5)=10ρ\operatorname{Cov}(X,Y)=\rho(2)(5)=10\rho

Model

Expand the variance, retaining the signed covariance cross term.

Var(Z)=32(22)+(2)2(52)+2(3)(2)(10ρ)\operatorname{Var}(Z)=3^2(2^2)+(-2)^2(5^2)+2(3)(-2)(10\rho)
=136120ρ=136-120\rho

Compute

The expression decreases with correlation, so choose the smallest feasible correlation.

ρ=1Var(Z)=136+120=256\rho=-1\quad\Longrightarrow\quad \operatorname{Var}(Z)=136+120=256

Answer

The largest possible variance is 256.

256(E)\boxed{256\quad\text{(E)}}

Why the other choices are wrong

A
The value 16 is the largest possible standard deviation, 3(2)+2(5). The question asks for variance, which is 16 squared.
B
The value 100 is (-2) squared times Var(Y). It keeps only the Y contribution and omits X and covariance.
C
The value 120 is the greatest possible magnitude of the covariance cross term. It omits both marginal variance terms.
D
The value 136 is 9(4)+4(25), obtained by setting correlation to zero. Independence is not given, and zero correlation does not maximize this expression.

Independent answer check

Primary value256
Primary methodExpand the correlated linear-combination variance as a function of rho and optimize it over [-1,1].
Independent value256
Independent methodThe standard-deviation bound for 3X-2Y is 3SD(X)+2SD(Y)=6+10=16. Perfect negative correlation between X and Y makes the two weighted random parts move together, attaining variance 16 squared=256.
AnswerE · agreement passed

Contents

Inside the 76-page edition

Candidates preparing in English for the Probability (P) Exam

Table of contents

  1. 30 original multivariate problems
  2. Joint, marginal, and conditional models
  3. Covariance and linear combinations
  4. Order statistics and independent sums
  5. Central limit theorem and error diagnostics

What is included

30 verified original variants selected without duplication for this focused diagnostic. Official problem wording is not included.

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Questions about this edition

Are these official sample questions?

No. Every question is an independently written original variant. Official problem wording is not reproduced.

Are complete solutions included?

Yes. Every problem includes Setup, Model, Compute, and Answer steps plus a concrete explanation for each of the four incorrect choices.

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Does this overlap the complete proof manual?

Yes. These 30 original variants are selected from the verified variant bank included in the Probability Proof Manual. This edition adds a curated focused diagnostic, answer sheet, answer key, and focused purchase price.

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Probability Multivariate & Risk Models Practice Workbook

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