Independent solution

How to solve this Geometrically Increasing Deposits question

Setup

Setup

Let X be the time-1 deposit. Deposit t is X times 1.092 to the power t minus 1 and then accumulates to time 10 at 4%.

Ct=X(1.092)t1C_t=X(1.092)^{t-1}

Model

Model

Write the time-10 value as a finite geometric sum of deposit growth and investment accumulation.

5000=Xt=110(1.092)t1(1.04)10t5000=X\sum_{t=1}^{10}(1.092)^{t-1}(1.04)^{10-t}

Compute

Compute

The accumulated-value factor is 17.902263. Dividing the target fund by this factor gives the first deposit.

X=500017.902263=279.2943X=\frac{5000}{17.902263}=279.2943

Answer

Answer

The first deposit rounds to 279, so the correct answer is D.

X279(D)\boxed{X\approx279\quad\text{(D)}}